DQ 2. Identify the anode and cathode in the Cu-Pb voltaic cell. Provide the balanced half-reactions that describe the reaction taking place at each electrode. Combine the two half-reactions to provide the net ionic equation that represents the overall reaction within the Cu-Pb voltaic cell.

Pb is the anode because it has a more negative reduction potential. This implies that it is above copper in the electrochemical series. In any voltaic cell comprising of a metal cathode and anode; the metal that is higher in the electrochemical series serves as the anode while the other metal serves as the cathode.

Histrionicus Histrionicus · Answer 2 · 2021-11-25T08:03:23+01:00

Identify the anode and cathode in the Cu-Pb voltaic cell -

Pb - cathode, Cu - anode

Half reactions: Pb 2+ (aq) + 2 e- ---> Pb (s)

Cu (s) ---> Cu 2+ (aq) + 2 e-

Combined reaction:

Cu (s) + Pb 2+ (aq) ---> Cu 2+ (aq) + Pb (s)

A galvanic cell or voltaic cell reaction is a redox reaction that takes place in two half-reactions oxidation and reduction. At anode oxidation reaction and at cathode reduction reaction takes place.

A copper metal electrode is inside the gel.
A metal ion solution that is Pb2+ is poured over the gel.
A corresponding metal electrode is placed in the solution.
The gel allows the copper metal to act as a voltaic cell with the metal ion solution.

to identify the oxidized and reduced atoms we must assign oxidation states to all atoms.

anode:

Cu (s) ---> Cu 2+ (aq) + 2 e-

cathode:

Pb 2+ (aq) + 2 e- ---> Pb (s)

combined:

Cu (s) + Pb 2+ (aq) ---> Cu 2+ (aq) + Pb (s)

Thus, Identify the anode and cathode in the Cu-Pb voltaic cell -

Pb - cathode, Cu - anode

Half reactions: Pb 2+ (aq) + 2 e- ---> Pb (s)

Cu (s) ---> Cu 2+ (aq) + 2 e-

Combined reaction:

Cu (s) + Pb 2+ (aq) ---> Cu 2+ (aq) + Pb (s)

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