Answer:
9.09m
Explanation:
vertical spring of force constant K =4 850 N/m
✓the mass under gravitational potential energy since it's on the top of the light
✓vertical spring of force constant 4 850 N/m is given which is under elastic potential energy
We can equate the elastic potential energy and the gravitational potential energy to have
mgh= ½·k·x²
From here we can make "h" the subject of the formula which is our maximum height above the point of release
h= (½·k·x²)/mg
h= 1/2[ ·k·x²)/mg]
Where k= vertical spring of force constant K =4 850 N/m
m= mass of block= 0.256 kg
g=acceleration due to gravity
x= spring compression= 0.097 m.
Substitute this values we have
h= [0.5× 4850 ×(0.097)^2]/(9.81×0.256)
h=9.0854m
maximum height above the point of release it rise is 9.09m
