Answer:
The magnetic field strength needed is 0.425 T.
Explanation:
Given;
radius of the coil, r = 0.25 m
number of turns of the coil, n = 500 turn
time, t = 4.17 ms = 4.17 x 10⁻³ s
angular frequency, ω = 60 rev/s
Area of the coil, A = πr² = π(0.25)² = 0.1964 m²
Average induced emf is given by;
[tex]emf = N\frac{\delta \phi}{\delta t}\\\\emf = \frac{NBA}{t}\\\\B = \frac{emf*t}{NA}\\\\B = \frac{10,000*4.17*10^{-3}}{500*0.1964}\\\\B = 0.425 \ T[/tex]
Therefore, the magnetic field strength needed is 0.425 T.
The number of magnetic flux lines on a unit area passing perpendicular is induced magnetic field strength. The magnetic field strength needed to induce an average emf will be 0.425 T.
The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.
The given data in the problem is;
r is the radius of the coil = 0.25 m
n is the number of turns of the coil500 turn
t is the time = 4.17 ms = 4.17 x 10⁻³ s
w is the angular frequency= 60 rev/s
A is the Area of the coil = π(0.25)² = 0.1964 m²
average emf = 10,000 V
The relation of emf is given by
[tex]\rm emf =\frac{N\delta \phi}{\delta t} \\\\emf =\frac{NBA}{ t}\\\\ \rm B= \frac{emf \times t}{NA} \\\\\rm B= \frac{emf \times 4.17 \times 10^{-3}}{500 \times 0.1964} \\\\ \rm B=0.425 \;T[/tex]
Hence the magnetic field strength needed to induce an average emf will be 0.425 T.
To learn more about the strength of induced magnetic field refer ;
https://brainly.com/question/2248956
