Respuesta :
Answer: A, Magnitude of 8 and direction angle equal to 0°
Step-by-step explanation:
Since vector u is only a straight line, there will be no angle, which means that answers B and D are automatically wrong.
Now, we’re going to use the distance formula to find the component form of vector u
[tex]\sqrt{(6-(-2)^2+(3-3)^2}\\\\\sqrt{(8)^2+(0)^2}[/tex]
Now we found the new coordinate, which is (8,0), and it is being extended from the origin with the same angle of 0°
Using the formula from above, we can find the magnitude of vector u
[tex]\sqrt{(8)^2+(0)^2} \\\\\sqrt{64+0}\\\\\sqrt{64}\\\\8[/tex]
Hope I explained it well and hopefully this helps!
The vector has a magnitude of 8 and a direction angle equal to 0°.
What is a Vector?
A vector is an object that has both magnitude and direction.
The vector u has an origin at (-2,3) and the terminal point is (6,3)
The magnitude of the vector can be determined by the distance formula
The magnitude is
[tex]|u| = \sqrt{ (3-3)^2 + ( 6+2)^2[/tex]
|u| = 8
It has a magnitude of 8
The angle will be equal to zero as it is a straight line.
Therefore, the vector has a magnitude of 8 and a direction angle equal to 0°.
To know more about Vector
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