Respuesta :

caylus
Hello,

2x²+8x+26=0
==>x²+4x+13=0
Δ=4²-4*13-36

x=(-4+6i)/2 or x=(-4-6i)/2

x=-2+3i  or x=-2-3i

Answer A

2x^2+8x=-26
divide both sides by 2
x^2+4x=-13
add 13 both sides
x^2+4x+13=0
a=1
b=4
c=13
x=[tex] \frac{-4+/- \sqrt{4^2-4(1)(13)} }{2(1)} [/tex]
x=[tex] \frac{-4+/- \sqrt{16-52} }{2} [/tex]
x=[tex] \frac{-4+/- \sqrt{-36} }{2} [/tex]
x=[tex] \frac{-4+/- (\sqrt{-1})(\sqrt{36}) }{2} [/tex]
x=[tex] \frac{-4+/- i\sqrt{36} }{2} [/tex]
x=[tex] \frac{-4+/- 6i}{2} [/tex]
x=-2+/-3i


solutions are
-2+3i and -2-3i