The number of grams : 17.082 g
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
[tex]\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}[/tex]
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
453.9 mL of 0.237 M calcium acetate
[tex]\tt mol=M\times V=0.237\times 0.4539=0.108[/tex]
MW Ca(C₂H₃OO)₂ : 158,17 g/mol
[tex]\tt mass=mol\times MW\\\\mass=0.108\times 158.17=17.082~g[/tex]