Answer:
[tex]\boxed{A=3 {x}^{4} + {5x}^{2} + 11x - 7}[/tex]
Step-by-step explanation:
[tex]
if \: its \: volume \: is \to \: \\ 12x^{5}- 27x^{4} + 20x^{3} - x^{2} - 127x + 63 \\ given \: the \: height \: is \to \\ 4x - 9 \\ then \: the \:a rea \: is \: given \: by \to \\ A= \frac{V}{h} .............where \: \boxed{v} \: is \: the \: volume \\ A= \frac{12x^{5}- 27x^{4} + 20x^{3} - x^{2} - 127x + 63 }{4x - 9 } \to\\ \\ 4x - 9 ) \frac{ \frac{3 {x}^{4} + {5x}^{2} + 11x - 7}{.....................................................} }{ \frac{12x^{5}- 27x^{4} + 20x^{3} - x^{2} - 127x + 63}{ \frac{ - (12x^{5}- 27x^{4}) }{ \frac{ \to \: 20x^{3} - x^{2} - 127x + 63}{ \frac{ -(20x^{3} - 45 {x}^{2} ) }{ \frac{ \to \: 44 {x}^{2} - 127x + 63}{ \frac{ - (44 {x}^{2} - 99x)}{ \frac{ \to \: - 28x + 63}{ \frac{ \frac{ - ( - 28x + 63)}{ \to \: 0} }{} } } } } } } } } \\ hence\: the \: area \: is \: given \: to \: be \to \\ \boxed{A=3 {x}^{4} + {5x}^{2} + 11x - 7}[/tex]
♨Rage♨
