Answer:
Probability (at least one bottle neck occurs during 8 hours of operation) = 0.9817
Explanation:
Given:
Average bottleneck 1 hour = 0.5
Find:
Probability (at least one bottle neck occurs during 8 hours of operation)
Computation:
Expected events in 8 hour = 8(0.5)
Expected events in 8 hour = 4
Probability (at least one bottle neck occurs during 8 hours of operation) = p(X≥1)
Probability (at least one bottle neck occurs during 8 hours of operation) = 1-p(X=0)
Probability (at least one bottle neck occurs during 8 hours of operation) =1-exp(-4)[4⁰]/0!
Probability (at least one bottle neck occurs during 8 hours of operation) =1-0.0183
Probability (at least one bottle neck occurs during 8 hours of operation) = 0.9817