Answer:
396.56 lbf
Explanation:
From the question given above, the following data were obtained:
Volume of rod = 0.3 m³
Specific gravity = 4.7
Gravitational acceleration (g) = 1.25 m/s²
Weight of rod =...?
Next, we shall determine the density of the rod. This can be obtained as follow:
Specific gravity = 4.7
Density of water = 1000 Kg/m³
Density of rod =...?
Specific gravity = Density of rod /Density of water
4.7 = Density of rod /1000
Cross multiply
Density of rod = 4.7 × 1000
Density of rod = 4700 Kg/m³
Next, we shall determine the mass of the rod. This can be obtained as follow:
Volume of rod = 0.3 m³
Density of rod = 4700 Kg/m³
Mass of rod =?
Density = mass /volume
4700 = Mass of rod / 0.3
Cross multiply
Mass of rod = 4700 × 0.3
Mass of rod = 1410 Kg
Next, we shall determine the weight of the rod. This can be obtained as follow:
Mass of rod = 1410 Kg
Gravitational acceleration (g) = 1.25 m/s²
Weight of rod =...?
Weight = mass × Gravitational acceleration
Weight of rod = 1410 × 1.25
Weight of rod = 1762.5 N
Finally, we shall convert 1762.5 N to pounds-force [lbf]. This can be obtained as follow:
1 N = 0.225 lbf
Therefore,
1762.5 N = 1762.5 N × 0.225 Lbf / 1 N
1762.5 N = 396.56 lbf
Therefore, the weight of the rod is 396.56 lbf
