Answer:
[CH₃COOH] = 0.813 M
Explanation:
First of all we need to know the base of any titration.
In any titration, when you reach the equivalence point we say that:
mmoles of acid = mmoles of base
mmoles of acetic acid = mmoles of Ca(OH)₂
We can know the mmoles of the hydroxide with the given information.
33.93 mL . 0.0599M = 2.03 mmoles of base
The thing is that the calcium hydroxide release 2 OH, then to neutralize all the acetic acid, we need double of hydroxides.
Ca(OH)₂ → Ca²⁺ + 2OH⁻
2.03 mmol 4.06 mmoles
These are the moles required to neutralize the acetic acid, because we said that in the equivalence point, mmoles of acid = mmoles of base
So, as Molarity can be defined as mmoles / mL
M = 4.06 mmoles/5mL → 0.813 M
