Answer:
2.62x10²⁰ photons are emitted per second.
Explanation:
The number of photons emitted per second can be found using the following equation:
[tex] E = \frac{hc}{\lambda} [/tex] (1)
Where:
h: is the Planck's constant = 6.62x10⁻³⁴ J.s
c: is the speed of light = 3.00x10⁸ m/s
λ: is the wavelength = 520 nm
E: is the energy = 100 J/s
Equation (1) gives the energy for a single photon, so if we have more than one we need to use the term "n" to indicate the number of photons:
[tex] E = \frac{nhc}{\lambda} [/tex]
By solving the above equation for n we have:
[tex] n = \frac{E \lambda}{hc} = \frac{100 J/s*520 \cdot 10^{-9} m}{6.62 \cdot 10^{-34} J.s*3.00 \cdot 10^{8} m/s} = 2.62 \cdot 10^{20} photons/s [/tex]
Therefore, 2.62x10²⁰ photons are emitted per second.
I hope it helps you!
The number of photons emitted per second is [tex]2.62 \times 10^{20} \;\rm photons/s[/tex].
Given data:
The power rating of bulb is, P = 100 W.
The rate of energy radiation is, E = 100 J/s.
The wavelength of light is, [tex]\lambda =520 \;\rm nm =520 \times 10^{-9} \;\rm m[/tex].
The number of photons emitted per second can be found using the following equation:
[tex]E=\dfrac{nhc}{\lambda}[/tex]
Here,
n is the number of photons emitted per second.
h is the Planck's constant.
c is the velocity of light.
Solve by substituting the values as,
[tex]100=\dfrac{n \times 6.63 \times 10^{-34} \times (3 \times 10^{8})}{520 \times 10^{-9}}\\\\n = 2.62 \times 10^{20} \;\rm photons/s[/tex]
Thus, we can conclude that the number of photons emitted per second is [tex]2.62 \times 10^{20} \;\rm photons/s[/tex].
learn more about the Planck's constant here:
https://brainly.com/question/3479109
