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The pressure of 8.40 L of nitrogen gas in a flexible container is decreased to one-half its original pressure, and its absolute temperature is increased to double the original temperature. What is the new volume?

Respuesta :

Eduard22sly

Answer:

33.6 L

Explanation:

From the question given above, the following data were obtained from:

Initial volume (V1) = 8.40 L L

Initial pressure (P1) = P

Initial temperature (T1) = T

Final pressure (P2) = one-half the original pressure = ½P

Final temperature (T2) = double the original temperature = 2T

Final volume (V2) =.?

Thus, the new volume of the gas can be obtained as follow:

P1V1/ T1 = P2V2 /T2

P × 8.40 / T = ½P × V2 /2T

P × 8.40 / T = P × V2 / 4T

Cross multiply

T × P × V2 = P × 8.40 × 4T

Divide both side by T × P

V2 = (P × 8.40 × 4T) /T × P

V2 = 8.40 × 4

V2 = 33.6 L

Thus, the new volume of the gas is 33.6 L

mahima6824soni

The pressure of 8.40 L of nitrogen gas in a flexible container is decreased to one-half its original pressure, the new volume is 33.6 L.

What is pressure?

Pressure is the force exerted in the perpendicular direction by any object.

By the Boyle's Law

\rm P_1V_1= P_1V_2

[tex]\rm \dfrac{P_1 \times 8.40}{T_1} = \dfrac{P_1V_2}{T_2} \\\\\dfrac{P \times 8.40}{T} = \dfrac{P \times V_2}{4T} \\\\T\times P \times V_2 = P \times 8.40 \times 4T\\\\V2 = 8.40 \times 4= 33.6 L\\[/tex]

Thus, the pressure of 8.40 L of nitrogen gas in a flexible container is decreased to one-half its original pressure, the new volume is 33.6 L.

Learn more about pressure

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