Respuesta :
The radius, r, of the circle is the distance from the center to any point on the circle.
r = √[(1-(-3))2+(5-2)2] = √25 = 5
An equation of the circle with center (h,k) and radius r is:
(x-h)2 + (y-k)2 = r2
So, in this problem, we have (x+3)2+(y-2)2=25.
To find a point on the circle with x-coordinate -7, replace x by -7 in the equation of the circle and solve for y:
(-7+3)2+(y-2)2 = 25
16 + (y-2)2=25
(y-2)2 = 9
y-2 = 3 or -3
So, y = 5 or -1
The points (-7,5) and (-7,-1) both lie on the circle.
r = √[(1-(-3))2+(5-2)2] = √25 = 5
An equation of the circle with center (h,k) and radius r is:
(x-h)2 + (y-k)2 = r2
So, in this problem, we have (x+3)2+(y-2)2=25.
To find a point on the circle with x-coordinate -7, replace x by -7 in the equation of the circle and solve for y:
(-7+3)2+(y-2)2 = 25
16 + (y-2)2=25
(y-2)2 = 9
y-2 = 3 or -3
So, y = 5 or -1
The points (-7,5) and (-7,-1) both lie on the circle.
