The mass of 4.87×10²⁵ atoms of Zn is 5.29 Kg
From Avogadro's hypothesis,
Recall,
1 mole of Zn = 65.38 g
Converting 65.38 g to Kilogram (Kg), we have:
1000 g = 1 Kg
Therefore,
65.38 g = 65.38 / 1000
Thus, we can say that,
Finally, we shall determine the mass of Zn that contains 4.87×10²⁵ atoms. This can be obtained as follow:
6.02×10²³ atoms = 0.06538 Kg of Zn
4.87×10²⁵ atoms = [tex]\frac{4.87*10^{25} * 0.06538}{6.02*10^{23} } \\\\[/tex]
Therefore, the mass of 4.87×10²⁵ atoms of Zn is 5.29 Kg
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