Answer: 1169.298 L
Explanation: In order to go from grams to liters, you must find the moles first using the molar mass, 62.068 g/mol (found via google search). I will assume the ethylene glycol is in gas form so we can use the 22.4 L per mol conversion.
Using dimensional analysis, starting with the kg, we must convert to grams, then moles, then liters.
[tex]\frac{3.24 kg}{} * \frac{1000g}{1 kg} * \frac{1 mol}{62.068 g} * \frac{22.4 L}{1 mol}[/tex]
Multiply the top individually, then the bottom individually.
[tex]\frac{72576}{62.068}[/tex]
Divide out.
[tex]= 1169.298 L[/tex]
In the end, we get 1169.298 L of ethylene glycol.
