Answer:
20 pig callers
Explanation:
Given that:
A pig caller produced intensity level of a sound = 107 dB
To find how many pig callers required to generate an intensity level of 120 dB;
we have:
120 dB - 107 dB = 13 dB
Taking the logarithm function;
[tex]10 \ log \bigg(\dfrac{I}{I_o} \bigg) = 13 \ dB[/tex]
where;
[tex]I_o[/tex] = initial intensity
[tex]log \bigg(\dfrac{I}{I_o} \bigg) = 1.3[/tex]
[tex]\dfrac{I}{I_o}= 10^{1.3 }[/tex]
I = 19.95[tex]I_o[/tex]
I ≅ 20 pig callers