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What is the empirical formula of a molecule containing 24% carbon (C), 6%
hydrogen (H), and 70% chlorine (CI)?
O A. CH3C1
B. C2H6Cl2
C. C24H6C170
O D. CHCI
SUBMIT

Respuesta :

Neetoo

Answer:

Empirical formula is CH₃Cl.

Explanation:

Given data:

Percentage of hydrogen = 6%

Percentage of carbon = 24%

Percentage of chlorine= 70%

Empirical formula = ?

Solution:

Number of gram atoms of H = 6/ 1 = 6

Number of gram atoms of C = 24 /12=  2

Number of gram atoms of Cl = 70/ 35.45 = 2

Atomic ratio:

            C                      :      H            :         Cl

           2/2                    :     6/2           :       2/2

            1                       :        3          :        1

C : H : Cl = 1 : 3 : 1

Empirical formula is CH₃Cl.

rykeir2

Answer:

CH3Cl

Explanation:

a-p-e-x

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