Answer:
The initial velocity of the plane is 54.77 m/s
Explanation:
Given;
distance covered by the plane, d = 200 m
deceleration of the plane, a = - 7.5 m/s²
The initial velocity of the plane is given by the following kinematic equation;
v² = u² + 2ad
where;
v is the final velocity of the plane when the plane comes to a complete stop = 0
u is the initial velocity of the plane
0 = u² + 2(-7.5 x 200)
0 = u² - 3000
u² = 3000
u = √3000
u = 54.77 m/s
Therefore, the initial velocity of the plane is 54.77 m/s
