A jar contains 42 red marbles numbered 1 to 42 and 36 blue marbles numbered 1 to 36. A marble is drawn at random from the jar. Find the probability of the given event. Please enter reduced fractions. (a) The marble is red. P(red)= Correct (b) The marble is odd-numbered. P(odd)= Correct (c) The marble is red or odd-numbered. P(red or odd) = Incorrect (d) The marble is blue or even-numbered. P(blue or even) =

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topeadeniran2 topeadeniran2 · Answer 1 · 2020-12-04T01:58:00+01:00

Answer: See explanation

Step-by-step explanation:

Number of red marbles = 42

Number of blue marbles = 36

Total number of marbles = 42 + 36 = 78

There are 21 odd numbers between 1 - 42.

There are 18 odd numbers between 1 - 36.

(a) Probability that the marble is red will be:

P(red)= 42 / 78 = 7 / 13

(b) Probability that the marble is odd-numbered will be:

= 39 / 78 = 1/2

(c) Probability that the marble is red or odd-numbered will be:

P(red or odd) = P(red) + p(odd) - P(odd and red)

= (42/78) + (39/78) - (21/78)

= 60/78

= 10/13

(d) Probability that the marble is blue or even-numbered.

= P(blue) + P(even) - P(blue and even)

= 36/78 + 39/78 - 18/78

= 57/78

= 19/26