Respuesta :
Answer:
10.76 grams
Explanation:
Given that the amount of [tex]KMnO_4[/tex] is 25.0 grams.
Mass of 1 mole of [tex]KMnO_4[/tex] = 158 grams
The number of atoms in 1 mole of [tex]KMnO_4[/tex] is 4.
Mass of oxygen in 1 mole of [tex]KMnO_4[/tex] = 16\times 4 = 68 grams.
Here, 158 grams of [tex]KMnO_4[/tex] has 68 grams of oxygen
So, the amount of oxygen in 1 gram of [tex]KMnO_4[/tex] = 68/158 grams
Therefore, the amount of oxygen in 1 gram of [tex]KMnO_4[/tex] = [tex]\frac {68}{158}\times 25[/tex] grams
=10.76 grams
Hence, 25 grams of [tex]KMnO_4[/tex] has 10.76 grams of oxygen.
The mass of oxygen in 25.0 grams of potassium permanganate , KMnO4 is 10.13 grams.
molar mass of KMnO₄ = 39 + 55 + 16(4)
molar mass of KMnO₄ = 39 + 55 + 64
molar mass of KMnO₄ = 158 grams
molar mass of oxygen in the compound = 64 g
Therefore,
158g of potassium permanganate has 64 g of oxygen
25 g of potassium permanganate will contain ? of oxygen
cross multiply
mass of oxygen = 25 × 64 / 158
mass of oxygen = 1600 / 158
mass of oxygen = 10.1265822785
mass of oxygen ≈ 10.13 grams
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