We are given:
Volume of Glucose solution = 144 mL OR 0.144 L
Molarity of Glucose solution = 0.280 M
Number of moles of Glucose in the solution:
From the definition of Molarity, we know that:
Molarity = number of moles / volume(in L)
in this equation, multiplying both sides by Volume, we get:
number of moles = Molarity*Volume(in L)
replacing the variables
Number of moles = 0.280*(0.144L)
Number of moles = 0.04
Number of Molecules in the solution:
We know that:
Number of molecules = Number of Moles * Avogadro's number
Number of molecules = 0.04 * 6.022 * 10²³
Number of molecules = 0.24088 * 10²³
Number of molecules = 2.4088 * 10²²
Therefore, there are 2.4088 * 10²² molecules of Glucose in the given solution
