(I) [tex]H_2SO_4+ 2NaHCO_3--> Na_2SO_4 + 2 H_2O + 2CO_2[/tex]
(II) [tex]H_2+I_2 --> 2HI[/tex]
(III) [tex]2NaOH+H_2SO_4--> Na_2SO_4+ 2H_2O[/tex]
(IV) [tex]2FeSO_4--> Fe_2O_3+SO_2+SO_3[/tex]
(V) [tex]2C_3H_6O_2+7O_2-->6CO_2+6H_2O[/tex]
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(I) [tex]H_2SO_4[/tex]
(ANS) [tex]98 \frac{grams}{mol}[/tex]
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Solution:
Molecular mass of,
H = 1
S = 32
O = 16
Now,
There are 2 atoms of Hydrogen, 1 atoms of Sulfur and 4 atoms of Oxygen present, thus,
[tex]H_2SO_4 = (1x2)+32+(16x4)[/tex]
[tex]H_2SO_4 = 98 \frac{grams}{mol}[/tex]
(II) [tex]CH_4[/tex]
(ANS) [tex]16 \frac{gram}{mol}[/tex]
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Solution:
Molecular Mass,
Carbon = 12
Hydrogen = 1
Now
There are 1 atom of Oxygen and 4 atoms of Hydrogen present, thus,
[tex]CH_4 = 12 + (1x4)[/tex]
[tex]CH_4 = 16\frac{grams}{mol}[/tex]
(III) [tex]NH_3[/tex]
(ANS) [tex]17 \frac{grams}{mol}[/tex]
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Solution:
Molecular Mass,
Nitrogen = 14 grams
Hydrogen = 1
Now,
There are 1 atoms of Nitrogen and 3 atoms of Hydrogen present, thus,
[tex]NH_3 = 14 + (1x3)[/tex]
[tex]NH_3 = 17 \frac{grams}{mol}[/tex]
56 71
x 35.5
[tex]X = \frac{56 x 35.5}{71}[/tex]
Simplify the equation
X = 28 grams
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Answer:
28 grams of Iron(fe) will react with chlorine.
