Respuesta :
Answer:
Length=8 Width=5
Step-by-step explanation:
Set this up as a system of equations with l standing for length and w standing for width.
w+3=l
l×w=40
Substitute rhe first equation into the 2nd one.
w(w+3)=40 --------> w^2+3w=40
Move all the terms to the left side
w^2+3w-40=0
Factor
(w+8) (w-5)
Set both factors equal to 0.
w+8=0 -----> w=-8
w-5=0 ------> w=5
Since distance cannot be negative we can eliminate -8. So w=5
Plug it back into any one of the equations and solve for l.
5+3=l -----> 8=l
So the answer is the length is 8 and the width is 5.
The dimensions of the rectangle are:
Length = 8 meters.
width = 5meters.
We are given that the length of a rectangle is 3 meters longer than its width and the area of a rectangle is 40 square meters.
We need to find the length and width of the rectangle.
What is a rectangle?
A rectangle is a closed 2-dimensional shape that has two dimensions, the length, and the width. Length is the longer side and width is the shorter side of the rectangle.
The area of a rectangle is given by :
A = Length x Width.
Let the area, length, and width of the rectangle be A, L, and W.
The length of a rectangle is 3 meters longer than its width.
We can write it as,
L = 3 + W
The area of a rectangle is 40 square meters.
We can write it as,
A = 40 square meters
We can write it as,
L x W = 40
Substituting L = 3 + W.
(3 + W) W = 40
[tex]3W + W^2 = 40\\W^2 + 3W = 40 \\W^2 + 3W - 40 = 0[/tex]
This is a quadratic equation and we will apply middle-term factorization.
[tex]W^2 + 3W - 40=0\\W^2 + (8-5)W - 40=0\\W^2 + 8W - 5W - 40=0\\W(W + 8) - 5 ( W + 8)=0\\(W+8)(W - 5)=0\\W+8 = 0~~and~~W-5=0\\W = -8~~and~~W=5[/tex]
The distance can not be negative so W = -8 is eliminated.
We have, W = 5
Substituting W = 5 in L = 3 + W.
We get,
L = 3 + 5 = 8
L = 8.
The dimensions of the given rectangle are:
Length = L = 8 meters.
Width = W = 5 meters.
Learn more about rectangles here:
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