Answer:
a) The jumper opens the parachute in 7.5 seconds.
b) The jumper opens the parachute in approximately 7.706 seconds.
c) There are two possible choices for the function:
Case a): [tex]Dom\{h(t)\} = [0\,s,7.5\,s][/tex], [tex]Ran\{h(t)\}=[1000\,ft,1900\,ft][/tex]
Case b): [tex]Dom\{h(t)\} = [0\,s,7.706\,s][/tex], [tex]Ran\{h(t)\}=[950\,ft,1900\,ft][/tex]
Step-by-step explanation:
Note: The equation presented in statement is incorrect. The correct formula for free fall is:
[tex]h(t)=-16\cdot t^{2}+1900[/tex] (1)
Where:
[tex]t[/tex] - Time, measured in seconds.
[tex]h[/tex] - Height above the ground, measured in feet.
a) If we know that [tex]h(t) = 1000\,ft[/tex], then the final instant of the free fall stage is:
[tex]-16\cdot t^{2}+1900 = 1000[/tex]
[tex]16\cdot t^{2} = 900[/tex]
[tex]t = 7.5\,s[/tex]
The jumper opens the parachute in 7.5 seconds.
b) How long is the jumper in free fall if the parachute opens at 950 ft?
If we know that [tex]h(t) = 950\,ft[/tex], then the final instant of the free fall stage is:
[tex]-16\cdot t^{2}+1900 = 950[/tex]
[tex]16\cdot t^{2} = 950[/tex]
[tex]t \approx 7.706\,s[/tex]
The jumper opens the parachute in approximately 7.706 seconds.
c) There are two possible choices for the function:
Case a): [tex]Dom\{h(t)\} = [0\,s,7.5\,s][/tex], [tex]Ran\{h(t)\}=[1000\,ft,1900\,ft][/tex]
Case b): [tex]Dom\{h(t)\} = [0\,s,7.706\,s][/tex], [tex]Ran\{h(t)\}=[950\,ft,1900\,ft][/tex]
