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C++ Write a program that initially asks a user to enter two positive integer numbers a and b. If either a or are zero or negative, the program terminates right away. Then, generate an array of 20 integer numbers, each randomly generated between a and b. If b happens to be greater than a, then the array must contain elements randomly generated between b and a. Display the whole array on the screen. After creating and displaying the array, the program shows:
[A]verage [S]um [F]ind Please choose an option: Then, if the user selects:
- A (lowercase or uppercase): the program computes and displays the average of all elements of the array
-A (lowercase or uppercase): the program computes and displays the average of all elements of the array
-F (lowercase or uppercase): the program asks the user to insert an integer number to be found in the array
If present, the program displays "Found in position number followed by the position of the first occurrence.
If not present, the program displays "Number not found in the array"

Respuesta :

Answer:

#include <iostream>

#include <algorithm>

using namespace std;

int main(){

   int a, b, c[20], search, maxi, mini, totalSum = 0;

   char option;

   int * p;

   cout<< "Enter value for a: ";

   cin>> a;

   cout<< "Enter value for b: ";

   cin>> b;

  if (a == 0 || b == 0){

      cout<< "Both values must be greater than zero.";

  } else if(a>b){

        maxi = a;

       mini = b;

   }

else{

        maxi = b;

        mini = a;

   }

    for (int i =0; i < 20; i++){

        c[i] = (rand() % maxi) + mini;

        totalSum += c[i];

    }

   cout << "Please choose an option: 1 , 2, 3 ";

   cin>> option;

   option = tolower(option);

   switch(option){

       case 1:

           cout << "The Average of the array items is: "<< totalSum/20;

           break;

        case 2:

           cout<< "The sum of the array items is: "<< totalSum;

           break;

       case 3:

            cout<< "Enter number to be searched: ";

            cin>> search;

             p = find (c, c+20, search);

             if (p != c+20)

{

                cout << "Element found in c array: " << *p << '\n';

             }else{

                 cout << "Element not found in c array\n";

             }

             break;

   }

}

Explanation:

The C++ source code prompts the user for the a,b, option and search values and executes either of the options from the switch statement.

GoldenRetreiverLover

Answer:

#include <iostream>

#include <algorithm>

using namespace std;

int main(){

int a, b, c[20], search, maxi, mini, totalSum = 0;

char option;

int * p;

cout<< "Enter value for a: ";

cin>> a;

cout<< "Enter value for b: ";

cin>> b;

if (a == 0 || b == 0){

cout<< "Both values must be greater than zero.";

} else if(a>b){

maxi = a;

mini = b;

}

else{

maxi = b;

mini = a;

}

for (int i =0; i < 20; i++){

c[i] = (rand() % maxi) + mini;

totalSum += c[i];

}

cout << "Please choose an option: 1 , 2, 3 ";

cin>> option;

option = tolower(option);

switch(option){

case 1:

cout << "The Average of the array items is: "<< totalSum/20;

break;

case 2:

cout<< "The sum of the array items is: "<< totalSum;

break;

case 3:

cout<< "Enter number to be searched: ";

cin>> search;

p = find (c, c+20, search);

if (p != c+20)

{

cout << "Element found in c array: " << *p << '\n';

}else{

cout << "Element not found in c array\n";

}

break;

}

}

Explanation:

The C++ source code prompts the user for the a,b, option and search values and executes either of the options from the switch statement. Is correct

Explanation:

Great work person above me! :)

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