Answer:
The input energy to engine 2 is [tex]E_2 = 3807.7\ J[/tex]
Explanation:
From the question we are told that
The efficiency of engine one is [tex]\eta_1 = 0.18[/tex]
The input energy required is [tex]E = 5500 \ J[/tex]
The efficiency of engine 2 is [tex]\eta_2 = 0.26[/tex]
Generally the workdone by the engine 1 is mathematically represented as
[tex]W_1 = E * \eta_1[/tex]
=> [tex]W_1 = 5500 * 0.18[/tex]
=> [tex]W _ 1= 990 \ J[/tex]
Generally the workdone by engine 2 is mathematically represented as
[tex]W _2= E_1 * \eta_2[/tex]
=> [tex]W _2 = E_1 * 0.26[/tex]
=> [tex]W_2 =0.26E_1[/tex]
From the question we are told that [tex]W_1 = W_2[/tex]
So
[tex]990 =W_2 =0.26E_1[/tex]
=> [tex]E_2 = 3807.7\ J[/tex]
