Answer:
A) 7kg
B) 0.044
Explanation:
a) Accordimg to Newton's second law
\sum F = ma
Fm - Ff = ma
Fm is moving force =15-5 = 10N
Ff is fictional force = 3N
m is the mass = ?
a Is the acceleration = 1m/s²
Substitute
10-3 = 1m
7 = m
Hence the mass of the body is 7kg
b) coefficient of friction is expressed as;
n = Ff/R
R is the reaction = mg
n =Ff/mg
Substitute
n = 3/7(9.8)
n = 3/68.6
n = 0.044
Hence the coefficient of friction is 0.044