Answer:
Trey lives 384 feet.
Step-by-step explanation:
Let the average rate be represented by s, and the distance by d.
speed = [tex]\frac{distance}{time}[/tex]
⇒ distance = speed x time
i.e d = s x t
On his first trip,
d = s x 8
d = 8s ............ 1
on his trip home, the average rate was 16 miles per hour faster, so that;
d = (s + 16) x 6
d = 6s + 96 ............ 2
Equation 1 and 2, we have;
8s = 6s + 96
8s - 6s = 96
2s = 96
s = 48
The average rate is 48 miles per hour.
Thus from equation 1 (also equation 2 can be used),
d = 48 x 8
= 384
Therefore, Trey lives 384 feet from the mountains.
