Answer:
The magnitude of the work done by the snake against friction is 402 J.
Explanation:
The work is given by:
[tex] W = F*d [/tex]
Where:
F: is the force
d: is the distance
The distance traveled by the snake is given by the perimeter of the circle:
[tex] P = 2\pi r = 2\pi 3.20 m = 20.1 m [/tex]
Now, the force in the direction of the movement is:
[tex] |\Sigma F| = F_{\mu} = \mu N = \mu W = 0.25*80.0 N = 20 N [/tex]
Finally, the work is:
[tex] W = F*d = 20 N*20.1 m = 402 J [/tex]
Therefore, the magnitude of the work done by the snake against friction is 402 J.
I hope it helps you!
