The percent yield : 73.5%
Given
Reaction
C+2H₂⇒CH₄
Required
The percent yield
Solution
mol of Carbon(as a limiting reactant) :
[tex]\tt \dfrac{100}{12}=8.3[/tex]
mol CH₄ based on C, and from equation mol ratio C : CH₄, so mol CH₄ = 8.3
Mass of Methane(theoretical yield) :
[tex]\tt mass=mol\times MW\\\\mass=8.3\times 16=133.3~g[/tex]
[tex]\tt \%~yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{98}{133.3}\times 100\%=73.5\%[/tex]