The displacement of a car is a function of time as follows: x(t)=25+3.0t², with x is in meters. Find the average velocity between t1 = 1.0s and t2 = 4.0s.

Explanation: Average Velocity is vector describing the total displacement of an object and the time taken to change its position. It is represented as:

[tex]v=\frac{\Delta x}{\Delta t}[/tex]

At t₁ = 1.0s, displacement x₁ is:

[tex]x(1)=25+3(1)^{2}[/tex]

x(1) = 28

At t₂ = 4.0s:

[tex]x(4)=25+3(4)^{2}[/tex]

x(4) = 73

Then, average speed is

[tex]v=\frac{73-28}{4-1}[/tex]

v = 15

The average velocity of a car between t₁ = 1s and t₂ = 4s is 15m/s

The displacement of a car is a function of time as follows: x(t)=25+3.0t², with x is in meters. Find the average velocity between t1 = 1.0s and t2 = 4.0s.​

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The displacement of a car is a function of time as follows: x(t)=25+3.0t², with x is in meters. Find the average velocity between t1 = 1.0s and t2 = 4.0s.