Answer:
f + g = [tex]\frac{x-1}{x+ 3}+\frac{x-3}{x+1}=\frac{x^{2}-1 }{(x+3)(x+1)}+\frac{x^{2}-9 }{(x+1)(x+3)}=\frac{2x^{2}-10 }{(x+1)(x+3)}[/tex]
Step-by-step explanation: