1. How much heat is produced if you heat .25 kg water from 25 degrees C to 100 degrees C. The specific heat of water is 4180 J/kg C.

Respuesta :

Answer:

Q = 78375 [J]

Explanation:

To solve this problem we must use the following ideal equation for the thermal energy of an element or substance depending on the temperature change.

[tex]Q=m*C_{p}*(T_{final}-T_{initial})[/tex]

where:

Q = heat [J]

m = mass = 0.25 [kg]

Cp = specific heat = 4180 [J/kg*C]

Tinitial = 25[°C]

Tfinal = 100 [°C]

[tex]Q =0.25*4180*(100-25)\\Q = 78375 [J][/tex]

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