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What is the total amount of heat released in kilojoules when 112.0 g water at 50.0∘C cools to form ice at −45.0∘C? Use the following values for calculations, as needed.

Properties of Water−−−−−−−−−−−−−−−−−−Specific Heats(∘C)gas=1.84 J/g∘Cliquid=4.184 J/g∘Csolid=2.09 J/g∘C
Heat of VaporizationΔHvap=40.7 kJ/molHeat of FusionΔHfus=6.01 kJ/mol

Respuesta :

Answer:

Q = 44.5 kJ

Explanation:

Given that,

Mass of water, m = 112 g

Water at 50.0°C cools to form ice at −45.0°C

We need to find the total amount of heat released. The formula for heat released is given by :

[tex]Q=mc\Delta T[/tex]

c is the specific heat of water, c = 4.184 J/g°C

So,

[tex]Q=112\times 4.184 \times (-45-50)\\\\Q=-44517.76\ J[/tex]

or

Q = -44.5 kJ

So, 44.5 kJ of heat is released.

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