Answer:
d = 1.65 m
Explanation:
Given that,
The speed of a ball, v = 3 m/s
A ball rolls a level table that is 1.5 m above the floor.
We can find how long the ball is in free fall. We can use the second equation of kinematics as follows :
[tex]s=ut+\dfrac{1}{2}gt^2[/tex]
u is the initial speed in the vertical direction
So,
[tex]s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 1.5}{9.8}} \\\\t=0.55\ s[/tex]
Now, using the formula of velocity.
[tex]v=\dfrac{d}{t}\\\\d=vt\\\\d=3\times 0.55\\\\d=1.65\ m[/tex]
So, the landing spot is at 1.65 m from the table.
