Answer:
1.2 mol N2 = 26.88 L
3 mol H2 = 67.2 L
0.5 mol CO2 = 11.2 L
10.3 L NO2 = 0.46 moles
67.2 L SO2 = 67.2 / 22.4 = 3 moles
89.6 L NO = 89.6 /22.4 = 4 moles
44.8 L NO2 = 92 grams
201.6 L H2 = 18 g
65 grams CO = 51.9 L
152 grams F2 = 89.6 L
Explanation:
1 mole of a gas occupies a volume of 22.4 L
(N = 14, O = 16, C = 12, H = 1, F = 19)
1.2 mol N2= 1.2 * 22.4 L = 26.88 L
3 mol H2 = 3 * 22.4 L = 67.2 L
0.5 mol CO2 = 0.5 * 22.4 L = 11.2 L
10.3 L NO2 = 10.3 / 22.4 L = 0.46 moles
67.2 L SO2 = 67.2 / 22.4 = 3 moles
89.6 L NO = 89.6 /22.4 = 4 moles
1 mole or 22.4 L of NO₂ has a mass of 46 g
44.8 L NO2 = (44.8 /22.4) * 46 grams = 92 grams
1 mole or 22.4 L of H₂ has a mass of 2 g
201.6 L H2 = (201.6 / 22.4) * 2 grams = 18 g
1 mole or 22.4 L of CO has a mass of 28 g
65 grams CO = 65/28 * 22.4 L = 51.9 L
1 mole of F₂ has a mass of 38 grams
152 grams F2 = 152/38 * 22.4 L = 89.6 L