Answer:
b
Explanation:
Let the wild type trait, the silver-white, be represented by A allele and the mutant trait, the golden color, be represented by a allele.
Heterozygous wild-type male fish would be Aa
Golden female fish would be aa
Aa x aa
Aa Aa aa aa
2/4 Aa = silver-white
2/4 aa = golden color
Hence, the percent likelihood of golden offspring is 2/4 or 50%.
The correct option is b.