Given:
The points are (5,40) and (0,10).
To find:
The equation for the trend line using the given points.
Solution:
If a line passes through two points, then the equation of the line is:
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
Two points are (5,40) and (0,10). So, the equation of trend line is
[tex]y-40=\dfrac{10-40}{0-5}(x-5)[/tex]
[tex]y-40=\dfrac{-30}{-5}(x-5)[/tex]
[tex]y-40=6(x-5)[/tex]
[tex]y-40=6x-30[/tex]
Adding 40 on both sides, we get
[tex]y=6x-30+40[/tex]
[tex]y=6x+10[/tex]
Therefore, the equation of trend line is [tex]y=6x+10[/tex].