Answer:
Mass = 206.38 g
Explanation:
Given data:
Mass of calcium chloride = 80.0 g
Mass of silver chloride formed = ?
Solution:
Chemical equation:
CaCl₂ + 2AgNO₃ → Ca(NO₃)₂ + 2AgCl
Number of moles of CaCl₂:
Number of moles = mass/molar mass
Number of moles = 80.0 g/ 110.98 g/mol
Number of moles = 0.72 mol
Now we will compare the moles of CaCl₂ and AgCl
CaCl₂ : AgCl
1 : 2
0.72 : 2/1×0.72 = 1.44 mol
Mass of silver chloride:
Mass = number of moles × molar mass
Mass = 1.44 mol × 143.32 g/mol
Mass = 206.38 g
