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In an engine, an almost ideal gas is compressed adiabatically to half its volume. In doing so, 2820 J of work is done on the gas.

Required:
a. How much heat flows into or out of the gas?
b. What is the change in internal energy of the gas?
c. Does its temperature rise or fall?

Respuesta :

okpalawalter8

Answer:

  1. [tex]Q=0[/tex]
  2. [tex]U=2820[/tex]
  3. Energy increases

Explanation:

From the question we are told that

Work done [tex]W=2820[/tex]

a)Generally the heat flow for an adiabatic process is 0 (zero)

[tex]Q= U + W =>0[/tex]

[tex]Q=0[/tex]

b)Generally Change in internal energy of gas is mathematically given by

Since [tex]W=-2820J[/tex]

Therefore

[tex]U=2820[/tex]

Giving

[tex]Q= 2820 -2820[/tex]

[tex]Q=O[/tex]

c)With increases in internal energy brings increase in temperature

Therefore

Energy increases

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