Answer:
The solution to the system of equations is:
[tex]x=10,\:y=4[/tex]
Step-by-step explanation:
Given the system of equations
[tex]\begin{bmatrix}5x-4y=34\\ -x+8y=22\end{bmatrix}[/tex]
Multiply -x+8y=22 by 5: -5x+40y=110
[tex]\begin{bmatrix}5x-4y=34\\ -5x+40y=110\end{bmatrix}[/tex]
so adding the equations
[tex]-5x+40y=110[/tex]
[tex]+[/tex]
[tex]\underline{5x-4y=34}[/tex]
[tex]36y=144[/tex]
solve 36y = 144 for y:
[tex]36y=144[/tex]
divide both sides by 36
[tex]\frac{36y}{36}=\frac{144}{36}[/tex]
Simplify
[tex]y=4[/tex]
For 5x-4y=34 plug in y=4
[tex]5x-4\cdot \:4=34[/tex]
[tex]5x-16=34[/tex]
Add 16 to both sides
[tex]5x-16+16=34+16[/tex]
Simplify
[tex]5x=50[/tex]
Divide both sides by 5
[tex]\frac{5x}{5}=\frac{50}{5}[/tex]
Simplify
[tex]x=10[/tex]
Therefore, the solution to the system of equations is:
[tex]x=10,\:y=4[/tex]
