Moles of Lithium phosphate : 0.495
Given
6 Li + Zn₃(PO₄)₂ ------- > 2 Li₃PO₄ + 3 Zn
Required
Moles of Lithium phosphate
Solution
moles of Zinc(Ar=65,38 g/mol) :
= mass : Ar
= 48.6 : 65.38
= 0.743
From equation, mol ratio of Zn : Li₃PO₄ = 3 : 2, so mol Li₃PO₄ :
= 2/3 x mol Zn
= 2/3 x 0.743
= 0.495