Answer:
The equation of a parallel line in the slope-Intercept form that contains the point (3,-2) is:
Step-by-step explanation:
The slope-intercept form of the line equation
y = mx+b
where
Given the equation of a line
y = 2x + 4
comparing with the slope-intercept form of the line equation
The slope of the line AB is m = 2
We know that the parallel lines have the same slope.
Thus, the slope of the new line is also 2.
now we have,
- The slope of new line m = 2
Using the point-slope form of the line equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
where m is the slope of the line and (x₁, y₁) is the point
substituting the values m = 2 and the point (x₁, y₁) = (3, -2)
[tex]y-y_1=m\left(x-x_1\right)[/tex]
y - (-2) = 2(x - 3)
y + 2 = 2x - 6
subtracting 2 from both sides
y + 2 - 2 = 2x - 6 - 2
y = 2x- 8
Therefore, the equation of a parallel line in the slope-Intercept form that contains the point (3,-2) is:
