Answer:
A. length = 23 cm; width = 5 cm
Step-by-step explanation:
So if 4 times the width would be [tex]4w[/tex] and 3 more than would be [tex] + 3[/tex], the equation would be [tex]l = 4w + 3[/tex]. If the perimeter is 56, then the new equation, [tex]2(4w + 3) + 2(w) = 56[/tex] can be formed. This simplifies to [tex]8w + 6 + 2w = 56[/tex], then to [tex]10w + 6 = 56[/tex], then to [tex]10w = 50[/tex], and finally, [tex]w = 5[/tex]. So the width is 5, and now plug it into the first equation.
[tex]l = 4(5) + 3[/tex], becomes [tex]l = 20 + 3[/tex], becomes [tex]l = 23[/tex].
So the dimensions are: length = 23 cm, width = 5 cm.
*And just to be sure, [tex]2(23 + 5) = 2(28) = 56[/tex] which is correct.
