Answer:
the diameter of the second pipe is 2.52 in
Explanation:
Given the data in the question;
We know that; the rate of flow is the same;
so
Av1 = Av2
v ∝ √h
[tex]\frac{A1}{A2}[/tex] = [tex]\frac{V2}{V1}[/tex]
[tex]\frac{A1}{A2}[/tex] = √( [tex]\frac{h2}{h1}[/tex] )
( π/4.D1² / π/4.D2² ) = √( [tex]\frac{h2}{h1}[/tex] )
( D1² / D2² ) = √( [tex]\frac{2h1}{h1}[/tex] ) since second is double of first
so
( D1² / D2² ) = √( [tex]\frac{2}{1}[/tex] )
3² / D2² = √2
D2²√2 = 9
D2² = 9/√2
D2² = 9 / 1.4142
D2² = 6.364
D2 = √ 6.364
D2 = 2.52 in
Therefore, the diameter of the second pipe is 2.52 in
