Answer:
[tex]\boxed {\boxed {\sf a= -17.9 \ m/s^2}}[/tex]
Explanation:
Acceleration is equal to the change in velocity over the change in time.
[tex]a=\frac{v_f-v_i}{t}[/tex]
The initial velocity is 35.8 meters per second. The final velocity is 0 meters per second when the car comes to a complete stop. The time is 2.0 seconds.
[tex]v_f= 0 \ m/s \\v_i= 35.8 \ m/s \\t= 2 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{0 \ m/s - 35.8 \ m/s }{2 \ s}[/tex]
Solve the numerator.
[tex]a= \frac{ -35.8 \ m/s} {2 \ s}[/tex]
Divide.
[tex]a= -17.9 \ m/s/s = -17.9 \ m/s^2[/tex]
The car's acceleration is -17.9 meters per square second. The acceleration is negative because the car was coming to a stop and slowing down.
