Answer:
H2SO4
Explanation:
Firstly,
2.056% hydrogen = 2.056g of H
32.69% Sulphur = 32.69g of S
65.26% oxygen = 65.26g of O
Next, we convert each mass into moles by dividing by their respective molar mass:
H = 1, S = 32, O = 16
H = 2.056/1 = 2.056mol
S = 32.69/32 = 1.021mol
O = 65.26/16 = 4.078mol
Next, we divide each mole value by the smallest mole value (1.021)
H = 2.056/1.021 = 2.01
S = 1.021/1.021 = 1
O = 4.078/1.021 = 3.99
Approximately the ratio of H to S to O is 2:1:4, hence, the empirical formula for H, S and O is H2SO4.
The empirical formula of a chemical compound is the simplest whole-number ratio of atoms present in a compound
The correct answer of the following is [tex]H_2SO_4[/tex]
The data is given as follows:-
We have to find the moles in the reaction.
The mas of the element is as follows:-
After solving the equation we get
[tex]H = \frac{2.056}{1} = 2.056mol\\\\S = \frac{32.69}{32} = 1.021mol\\\\O = \frac{65.26}{16} = 4.078mol[/tex]
Next, we divide each mole value by the smallest mole value (1.021)
[tex]H = \frac{2.056}{1.021} = 2.01\\\\S = \frac{1.021}{1.021} = 1\\\\O = \frac{4.078}{1.021} = 3.99[/tex]
The ratio of H to S to O is 2:1:4,
Hence, the empirical formula for H, S, and O is [tex]H_2SO_4.[/tex]
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https://brainly.com/question/15804584
