A gas occupies 3.60 L when the temperature is 45.0oC and at 1.02 atm of pressure. What temperature change (in K) will be needed to change the volume to 6.25 L at constant pressure?
as we know V1/T1=V2/T2 so, V1=3.60 V2=6.25 T1=45c=318k T2=required solution! T2=V2 multiply by T1/V1 so put the values and find your answer which should be 552k
