The amount of thermal energy absorbed by the water : Q = 40,794 J
Given
150 ml water
Temperature = 22 °C to 87 °C
specific heat of water = 4.184 J/g°C
Required
Heat absorbed
Solution
Heat can be formulated :
Q = m.c.Δt
Q = 150 g x 4.184 J/g°C x (87-22)
Q = 40,794 J