Respuesta :

Answer:

C₃H₂Cl

Explanation:

From the question given above, the following data were obtained:

Mole of carbon (C) = 0.9887 mole

Mole of Hydrogen (H) = 0.6591 mole

Mole of Chlorine (Cl) = 0.3295 mole

Empirical formula =?

The empirical formula for the compound can be obtained as follow:

C = 0.9887 mole

H = 0.6591 mole

Cl = 0.3295 mole

Divide by the smallest

C = 0.9887 / 0.3295 = 3

H = 0.6591 / 0.3295 = 2

Cl = 0.3295 / 0.3295 = 1

Thus, the empirical formula for the compound is => C₃H₂Cl